(9x^2-12x+4)=(7x^2-3x)

Solution for (9x^2-12x+4)=(7x^2-3x) equation:

(9x^2-12x+4)=(7x^2-3x)

We move all terms to the left:

(9x^2-12x+4)-((7x^2-3x))=0

We get rid of parentheses

9x^2-12x-((7x^2-3x))+4=0


We calculate terms in parentheses: -((7x^2-3x)), so:

(7x^2-3x)

We get rid of parentheses

7x^2-3x

Back to the equation:

-(7x^2-3x)


We get rid of parentheses

9x^2-7x^2-12x+3x+4=0

We add all the numbers together, and all the variables

2x^2-9x+4=0

a = 2; b = -9; c = +4;
Δ = b2-4ac
Δ = -92-4·2·4
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-7}{2*2}=\frac{2}{4}
=1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+7}{2*2}=\frac{16}{4}
=4
$